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(2-4x+5x^2)=2x
We move all terms to the left:
(2-4x+5x^2)-(2x)=0
We get rid of parentheses
5x^2-4x-2x+2=0
We add all the numbers together, and all the variables
5x^2-6x+2=0
a = 5; b = -6; c = +2;
Δ = b2-4ac
Δ = -62-4·5·2
Δ = -4
Delta is less than zero, so there is no solution for the equation
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